3C+2K2Cr2O7+8H2SO4→2K2SO4+3CO2↑+2Cr2(SO4)3+8H2O
2个回答
C从0价被氧化到+4价
所以1molCO2~4mole-
0.8mol电子,就是0.2molCO2
标况下体积为
22.4*0.2=4.48L
相关问题
K2Cr2O7+H2SO4+K2SO3=K2SO4+Cr2(SO4)3+H2O
C+K2Cr2O7+H2SO4 ------ CO2+Cr2(SO4)3+K2SO4+H2O 配平
_K2Cr2O7+_H2SO4+_FeSO4=>_Fe2(SO4)3+_K2SO4+_Cr2(SO4)3+_H2O
2K2Cr2O7+3C2H5OH+8H2SO4=2K2SO4+2Cr(SO4)3+3CH3COOH+11H2O是否为还原
2K2Cr2O7+3CH3CH2OH+8H2SO4--2Cr2(SO4)3+ 3CH3COOH+2K2SO4+11H2O
K2Cr2O7+CH3CH2OH+H2SO4--Cr2(SO4)3+CH3COOH+K2SO4+H2O
2K2Cr2O7+3CH3CH2OH+8H2SO4=2Cr2(SO4)3+3CH3COOH+2K2SO4+11H2O 的
K2Cr2O7与乙醇的反应.K2Cr2O7与乙醇 2K2Cr2O7+3CH3CH2OH+8H2SO4--2Cr2(SO4
h2o2+cr2(so4)3+ X(未知)====k2so4+k2cr04+h20
H2O2+Cr2(SO4)3+KOH --K2SO4+K2CrO4+H2O