Question

解关于x的方程:mx^2+m^2x+x=nx^2+n^2x-m-n

Answer 1

1.当m≠n时

(m-n)x^2+(m^2-n^2)x+(x+m+n)=0

(m-n)x^2+(m+n)(m-n)x+(x+m+n)=0

(m-n)x(x+m+n)+(x+m+n)=0

[(m-n)x+1](x+m+n)=0

(m-n)x+1=0或x+m+n=0

所以x=1/(n-m)或x=-m-n

2.当m=n时

x=-m-n