Question

用大学方法求导数的隐函数

Answer 1

1）两边对x求导：2yy'-3y-3xy'=0

(2y-3x)y'=3y

y'=3y/(2y-3x)

2) 两边对x求导：-sin(xy)* (xy)'=1

-sin(xy)*(y+xy')=1

y+xy'=-1/sin(xy)

y'=-1/(xsin(xy))-y/x