请问不同浓度乙醇溶液的配制公式是什么

3个回答

  • 乙醇溶液密度(g/cm3)(20℃)-每g含有乙醇重量(%)-浓度(体积比%)=度(1度=1%体积)

    0.998-0.15-0.2

    0.996-1.20-1.5

    0.994-2.30-3.0

    0.992-3.50-4.4

    0.990-4.70-5.9

    0.988-5.90-7.4

    0.985-7.90-9.9

    0.982-10.0-12.5

    0.980-11.5-14.2

    0.978-13.0-16.0

    0.975-15.3-18.9

    0.972-17.6-21.7

    0.970-19.1-23.5

    0.968-20.6-25.3

    0.965-22.8-27.8

    0.962-24.8-30.3

    0.960-26.2-31.8

    0.957-28.1-34.0

    0.954-29.9-36.1

    0.950-32.2-38.8

    0.945-35.0-41.3

    0.940-37.6-44.8

    0.935-40.1-47.5

    0.930-42.6-50.2

    0.925-44.9-52.7

    0.920-47.3-55.1

    0.915-49.5-57.4

    0.910-51.8-59.7

    0.905-53.9-61.9

    0.900-56.2-64.0

    0.895-58.3-66.2

    0.890-60.5-68.2

    0.885-62.7-70.2

    0.880-64.8-72.2

    0.875-66.9-74.2

    0.870-69.0-76.1

    0.865-71.1-77.9

    0.860-73.2-79.7

    0.855-75.3-81.5

    0.850-77.3-83.3

    0.845-79.4-85.0

    0.840-81.4-86.6

    0.835-83.4-88.2

    0.830-85.4-89.8

    0.825-87.3-91.2

    0.820-89.2-92.7

    0.815-91.1-94.1

    0.810-93.0-95.4

    0.805-94.4-96.6

    0.800-96.5-97.7

    0.795-98.2-98.9

    0.791-99.5-99.7

    从中可以计算出:每(g/cm3)含有乙醇重量(%)g

    浓度(体积比%)=度(1度=1%体积)

    例如:密度为0.791g/cm3

    每(g/cm3)含有乙醇重量:0.791×99.5%=0.787045g

    浓度:99.7%=99.7度