Question

mn(m-n)-m(n-m)的平方因式分解==多少?

Answer 1

mn(m-n)-m(n-m)^2=-mn(n-m)-m(n-m)^2

=(n-m)[-nm-m(n-m)]

=(n-m)(-nm-mn+m^2)

=(n-m)(m^2-2m)

=m(n-m)(m-2)