Question

（x的4次方-4x²+1）（x的四次方+3x²+1）+10x的四次方-------------因式分

Answer 1

(x^4-4x^2+1)(x^4+3x^2+1)+10x^4

=[(x^4+1)-4x^2][(x^4+1)+3x^2]+10x^4

=(x^4+1)^2-x^2(x^4+1)-12x^4+10x^4

=(x^4+1)^2-x^2(x^4+1)-2x^4

=(x^4+1-2x^2)(x^4+1+x^2)

=(x^2-1)^2(x^4+x^2+1)

=(x+1)^2(x-1)^2(x^4+x^2+1)