Question

:已知方程组{ax+5y=15 ①,4x-by=-2 ②}

Answer 1

x=-3,y=-1满足方程4x-by=-2,即-12+b=-2,b=10；

x=5,y=4满足方程ax+5y=15 ,即5a+20=15,a=-1

故原方程组为

-x+5y=15

4x-10y=-2

解得x=14,y=29/5

x-y=41/5