Question

如图,已知在四边形ABCD中,AD∥BC,∠ABC=90°,DE⊥AC于点F,交BC于点G,交AB的延长线于点E,且AE

Answer 1

∵ AE=AC ∠AFE =∠ABC =90 ∠CAE =∠CAE

∴ △ABC ≌ △AFE

AF=AB

∵ AE=AB+BE AC=AF+CF

∴ BE=CF

∵ ∠EBG =∠CFG=90 ∠BGE =∠CGF

∴ △BEG ≌ △FCG

BG = FG