Question

f(x)=sin^2(x+π/6)+cos^2(x+π/3) 求最大值和最小值

Answer 1

f(x) =[1-cos(2x+π/3)]/2 +[1-cos(2x+2π/3)]/2

=1- (cos2x)/2

再看就知道f(x)max=f(π/2)=1+1/2=3/2

f(x)min=f(0)=1- 1/2=1/2