Question

求函数f(x)=sin(π/3-2想）+cos(π/6+2x）（x属于[π/4,π/2]）的最大值和最小值

Answer 1

f(x)=cos[π/2-(π/3-2x)]+cos(π/6+2x)

=cos(π/6+2x)+cos(π/6+2x)

=2cos(π/6+2x)

π/2