Question

为什么f(x)=(1-x)/ax+lnx的导数 f'(x)=-1/ax²+1/x=(ax-1)/ax&sup2

Answer 1

f(x)=(1-x)/ax+lnx

=1/ax-1/a+lnx

f'(x)=(1/ax)'-(1/a)'+(lnx)'

=1/a(1/x)'+0+1/x

=-1/ax^2+1/x

=-1/ax^2+ax/ax^2

=(ax-1)/ax^2