x=1 y=4 z=2
{3x+2y+z=13 {x+y+z=7 {2x+3y-z=12
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{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z
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方程只要答案：1,x+y+z=2 2y-3z=1 2x-y+3z=-12,已知（x-y+2z)/3=（y-z+2x）/7