问几道初二分式计算题,急用,对了我在追20分

2个回答

  • ^是次方

    2) 原式=(2x/((x-2)(x+2))-(x+2)/((x-2)(x+2)))*(x+2)/(x-1)

    =(x-2)/((x-2)(x+2))*(x+2)/(x-1)

    =1/(x-1)

    当x=√2+1时,原式=1/(√2+1-1)=1/√2=√2/2

    3) 原式=((x+y)/((x-y)(x+y))+(x-y)/((x-y)(x+y)))*(x^2-y^2)/(x^2y)

    =2x/(x^2-y^2)/(x^2-y^2)/(x^2y)

    =2/(xy)

    当x=√2+1,y=√2-1时,原式=2/((√2+1)(√2-1))=2/1=2

    4) 原式=(3x(x+1)/((x-1)(x+1))-x(x-1)/((x-1)(x+1)))*(x^2-1)/x

    =(3x^2+3x-x^2+x)/(x^2-1)*(x^2-1)/x

    =(2x^2+4x)/x

    =2x+4

    当x=√2-2时,原式=2(√2-2)+4=2√2

    5) 原式=((x+1)/(x(x-1))-x/(x-1)^2)*x

    =x((x+1)(x-1)/(x(x-1)^2)-x^2/(x(x-1)^2))

    =x(x^2-1-x^2)/(x(x-1)^2)

    =-1/(x-1)^2

    当x=√2+1时,原式=-1/(√2+1-1)^2=-1/2

    3.1) 原式=a-1+(a+1)(a-1)/(a-1)

    =a-1+a+1

    =2a

    当a=6时,原式=2*6=12

    3.2) 原式=-a/2+1+(a+1)(a-1)/(a-1)

    =-a/2+1+a+1

    =a/2+2

    当a=4时,原式=4/2+2=4

    3.3) 原式=((x+1)/((x+1)(x-1))+(x-1)/((x+1)(x-1)))*x^2/(x^2-1)

    =2x/(x^2-1)*x^2/(x^2-1)

    =2x^3/(x^2-1)^2

    当x=√2时,原式=2*(√2)^3/(2-1)^2=4√2/1=4√2

    4) 原式=3(x+1)/x*((x+1)/((x+1)(x-1))+(x-1)/((x+1)(x-1)))*x/6

    =(x+1)/2*(2x)/((x+1)(x-1))

    =x/(x-1)

    当x=√3+1时,原式=(√3+1)/(√3+1-1)=(√3+1)/√3=(3+√3)/3