n(Mg)=2 n(Al2so43)=6.5-2=4.5
so n(Al)=3
Mg要2mol苛性钠,成沉淀
Al要4mol,成溶液,这就分开了
所以,要(4x3+2x2)x0.2=16molx0.2=3.2mol
c(naoh)=1.6
so 2L
n(Mg)=2 n(Al2so43)=6.5-2=4.5
so n(Al)=3
Mg要2mol苛性钠,成沉淀
Al要4mol,成溶液,这就分开了
所以,要(4x3+2x2)x0.2=16molx0.2=3.2mol
c(naoh)=1.6
so 2L