Question

已知x的3n-2次方除以x的n+1次方=x的3-n次方乘以x的n+2次方（x不等于正负1）,求n的值?

Answer 1

x^(3n-2)÷x^(n+1)=x^(3-n)*x^(n+2)

x^(3n-2-n-1)=x^(3-n+n+2)

x^(2n-3)=x^5

2n-3=5

2n=8

n=4