Question

x的m次方乘以x的n次幂的3次方除以（x的m-1次方乘以2x的n-1次方）等于多少啊?

Answer 1

(x^m)*(x^n)³÷[x^(m-1)*2x^(n-1)]

=x^(m+3n)÷2x^(m+n-2)

=(1/2)x^[(m+3n)-(m+n-2)]

=(1/2)x^(2n+2) ----------即1/2倍的“x的(2n+2)次方”.