Question

怎样用matlab生成下面的矩阵

Answer 1

clc

clear

A=zeros(1,4);

for i=1:2^4-1

a=dec2bin(i);

n=numel(a);

m=4-n;

k=[];

for j=1:n

k=[k,str2num(a(j))];

end

temp=[zeros(1,m),k];

A=[A;temp];

end

A

结果

A =

0000

0001

0010

0011

0100

0101

0110

0111

1000

1001

1010

1011

1100

1101

1110

1111

挺笨的方法,仅供参考.