Question

8年级分式化简2

Answer 1

原式=2x/(x+2y)(x-2y)-2/(x-2y)+1=2x/(x+2y)(x-2y)-2(x+2y)/(x-2y)(x+2y)+(x+2y)(x-2y)/(x+2y)(x-2y)=(2x-2x-4y+xx-4yy)/(x+2y)(x-2y)=(xx-4y-4yy)/(x+2y)(x-2y)