求lim趋向于无穷3^n+(-2)^n/3^(n+1)+(-2)^(n+1)
1个回答
上下同除以3^n,变为[1+(-2/3)^n]/[3+(-2)*(-2/3)^n]
所以答案为1/3
相关问题
求极限lim n趋向于无穷(1/n)*√(n+1)(n+2)⋯(n+n)
求lim(-1+3^n)/2^(n+1)的极限(N趋向正无穷)
求极限 n趋向于无穷 lim((根号下n^2+1)/(n+1))^n
求lim n趋向于无穷 n(n^1/n -1)/ln n
lim n趋向于无穷(1/n^2+2/n^2+…+n/n^2)=?lim x趋向于正无穷{根号下(x^2+x)-根号下(
求lim 2^n-(-1/2)^n 的值.n趋向无穷 ---------------- 2^n+(-1/2)^n
lim(1+3+.+3^n)/(3^n+2^n)是多少 n趋向正无穷的极限
lim(n趋向于∞)[1/(n^2+1)+3/(n^2+1)+…+2000/(n^2+1)]
当n趋向于无穷时,为什么lim(1-cos(1/n)=1/2n^2
求极限 lim(x趋向于无穷)【(1/(n^2+1)^(1/2))+(1/(n^2+2)^(1/2))+.+(1/(n^