Question

6X=4y=3z 求x+y+z分之x+y-z的值

Answer 1

令a=6X=4y=3z

x=a/6

y=a/4,z=a/3

所以原式=(a/6+a/4+a/3)分之(a/6+a/4-a/3)

=3a/4分之a/12

=9