Question

如图,Rt△ABC的斜边长是5,两条直角边AC,BC的长分别是关于x的方程x^2+(2m-1)x+m^2+3=0

Answer 1

显然,x1+x2=1-2m,x1*x2=m^2+3,x1^2+x2^2=25于是,（x1+x2）^2=(1-2m)^2得到：x1^2+x2^2+2*x1*x2=1-4m+4m^2所以,25+6+2m^2=1-4m+4m^2故：m=5或m=-3