求值域要具体步骤：y=cosx ①x∈[π/6,π/3]②x∈[-π/6,2π/3]③x∈[-2π/3,4π/3]
①x∈[π/6,π/3]
定义域在第一象限,0
求值域要具体步骤：y=cos ①x∈[π/6,π/3]②x∈[-π/6,2π/3]③x∈[-2π/3,4π/3]
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