2*（-π/3）+π/3﹤2x+π/3≦2*π/6+π/3
-π/3﹤2x+π/3≦2π/3
-√3/2﹤sin(2x+π/3)≦1
-1/2﹤cos(2x+π/3)≦1
0≦2cos^2(2x+π/3)≦2
-√3/2﹤sin(2x+π/3)+2cos^2(2x+π/3)≦3
f(x)∈(-√3/2,3]
方法如上,算的对不对也懒得检查了,参考着看下吧……
求函数f(x)=sin(2x+π/3)+2cos^2(2x+π/3),x∈(-π/3,π/6]的值域
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