设函数f(x)sin(x+π/3)+2sin(x+

设函数f(x)sin(x+π/3)+2sin(x+π/3)-根号3cos(2π/3-x) （1）求f(π/6),f(π/

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设函数f(x)=sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
f(x)=cos(x+π/6）cos(x-2π/3)+sin(x+π/6)sin(x+π/3) 求函数F（X）的单调递减
已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)]
求函数f(x)=sin(2x+π/3)+2cos^2(2x+π/3),x∈(-π/3,π/6]的值域
已知 f(x)= sin(x-3π)•cos(2π-x)•sin(-x+ 3π 2 ) cos(-x-π)•cos( π
f(x)sinx·sin(π-x)+√3sin(π/2+x)cos(π/2+x)+2cos(π+x)cos(π-x) 求
已知函数F(X)=2sin(X+π/2)cos(x+π/2）+2根号3cos^2(x+π/2)-根号3（1）求f(x)的
已知f(x)＝sin(x−3π)•cos(2π−x)•sin(−x+3π2)cos(−x−π)•cos(π2−x)
f(x)=根号3/2sinπx+1/2cosπx
已知函数f(x)=2cos(x+π/3)[sin(x+π/3)-√3cos(x+π/3)]