三式相加得x+y+z=(a+b+c)/2
再把三式带入就可得:
x=(a+b+c)/2-b
y=(a+b+c)/2-c
z=(a+b+c)/2-a
因为ay
实数x,y,z满足x+y=a,y+z=b,x+z=c,且a
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