f(x)=1/2(cos²x+2√3cosxsinx+3sin²x)
=1/2(cosx+√3sinx)²
=1/2[2sin(x+π/6)]²
=2sin²(x+π/6)
f（x）=1／2cos^2x+根号3sinxcosx+3／2sin^2x 怎么化简
1个回答
相关问题
-
f(x)=sin(x^2)+(√3)sinxcosx+2cos(x^2) 化简
-
f(x)=sin(x^2)+(√3)sinxcosx+2cos(x^2) 化简
-
f (x)=-根号2sin²x+根号2sinxcosx 怎么化简、、
-
f(x)=2根号3sinxcosx+2cos²x+m,化简,
-
函数f（x）=—根号3sin^2x+sinxcosx 化简
-
化简sin(2x+π/3)-（根号3）sin²x+sinxcosx+(根号3)/2
-
怎么化简√3cos^x+sinxcosx-√3/2为sin(2x+ π 3 )
-
y=根号2(cos^2x-sin^2x)+2根号2sinxcosx化简
-
先化简y=sin^2x+2根号3sinxcosx+3cos^2x.在求值域
-
fx=2根号3sinxcosx+cos2x+1化简