∵AD∥BC
∴∠DEF=EFG=55°
∵D`E是DE沿EF折叠所得
∴∠D`EF=∠DEF=55°
∴∠AEG=180°-∠D`EF-∠DEF=70°
∠EGB=180°-∠AEG=110°
望采纳