由题意可设圆的方程为λ(x2+y2-4x+2y)+(x2+y2-2y-4)=0,(λ≠-1)即(1+λ)x2+(1+λ)y2-4λx+(2λ-2)y-4=0,圆心坐标为(,),代入l:2x+4y=1,得λ=3.所以所求圆的方程为x2+y2-3x+y-1=0.
望采纳哦 亲!
由题意可设圆的方程为λ(x2+y2-4x+2y)+(x2+y2-2y-4)=0,(λ≠-1)即(1+λ)x2+(1+λ)y2-4λx+(2λ-2)y-4=0,圆心坐标为(,),代入l:2x+4y=1,得λ=3.所以所求圆的方程为x2+y2-3x+y-1=0.
望采纳哦 亲!