(1-√3)y^2=(1+√3)y
=(1+√3)y (y-1)=0,y=0或y=1
(x-1)(x+3)-2(x+3)^2+3(x-3)(x+3)=0
(x+3)(x-1-2x-6+3x-9)=0
(x+3)(2x-15)=0
x=-3或x=15/2
用因式分解法解下列方程(1-√3)y^2=(1+√3)y
(1-√3)y^2=(1+√3)y
=(1+√3)y (y-1)=0,y=0或y=1
(x-1)(x+3)-2(x+3)^2+3(x-3)(x+3)=0
(x+3)(x-1-2x-6+3x-9)=0
(x+3)(2x-15)=0
x=-3或x=15/2