由(l) C(s)+1/2O 2(g)=CO(g)△H 1=-110.5kJ/mol,
(2)2H 2(g)+O 2(g)=2H 2O(g)△H 2=-483.6kJ•mol -1,
依据盖斯定律可知,(1)-(2)÷2即得到:C(s)+H 2O(g)═CO(g)+H 2(g),所以△H 3=-110.5kJ/mol+483.6kJ/mol÷2=+131.3kJ/mol,
故选A.
由(l) C(s)+1/2O 2(g)=CO(g)△H 1=-110.5kJ/mol,
(2)2H 2(g)+O 2(g)=2H 2O(g)△H 2=-483.6kJ•mol -1,
依据盖斯定律可知,(1)-(2)÷2即得到:C(s)+H 2O(g)═CO(g)+H 2(g),所以△H 3=-110.5kJ/mol+483.6kJ/mol÷2=+131.3kJ/mol,
故选A.