Question

求r=三次根下3V/4π的导数,因为我是预习的新课,所以麻烦写详细点,

Answer 1

=(3V/4π)^(1/3)=(3/4π)^(1/3)*V^(1/3)

所以r'=(3/4π)^(1/3)*[V^(1/3)]'

=(3/4π)^(1/3)*[(1/3)*V^(1/3-1)]

=(3/4π)^(1/3)*(1/3)*V^(-2/3)

=(1/36π)*1/三次根下V^2