∫x*ln(x-1)dx

2个回答

  • 用分步积分

    ∫x*ln(x-1)dx

    =1/2∫xln(x-1)dx^2

    =1/2x^2ln(x-1)-1/2∫x^2dln(x-1)

    =1/2x^2ln(x-1)-1/2∫x^2/(x-1)dx

    =1/2x^2ln(x-1)-1/2∫(x^2-1+1)/(x-1)dx

    =1/2x^2ln(x-1)-1/2∫[x+1+1/(x-1)]dx

    =1/2x^2ln(x-1)-1/4x^2-x/2-1/2ln(x-1)+C