已知函数f(tanx)=sin2x,x∈(-π/2,π/2),则f(1/2)=
1个回答
sin2x=[2tanx]/[1+tan²x]
又:
f(tanx)=sin2x=[2tanx]/[1+tan²x]
则:
f(x)=(2x)/(1+x²)
f(1/2)=4/5
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