设甲蜗牛爬行X米,则乙蜗牛爬行(1-3/5)X米.
(1-3/5)X÷3/5+3/5=X解方程可得X=9/5
竹竿长:9/5+(1-3/5)×9/5=63/25(米)
设竹竿长y米.
(Y-3/5)×3/(3+5)=〖(Y-3/5)×3/(3+5)+3/5〗× (1-3/5)
解方程可得y=63/25
如果能用得上请采纳.
设甲蜗牛爬行X米,则乙蜗牛爬行(1-3/5)X米.
(1-3/5)X÷3/5+3/5=X解方程可得X=9/5
竹竿长:9/5+(1-3/5)×9/5=63/25(米)
设竹竿长y米.
(Y-3/5)×3/(3+5)=〖(Y-3/5)×3/(3+5)+3/5〗× (1-3/5)
解方程可得y=63/25
如果能用得上请采纳.