x+2y+z=11,x+y+2z=12,2x+y+z=13
2个回答
三式相加
4x+4y+4z=11+12+13=36
x+y+z=9.(4)
分别减去(4)式得
x=4,y=2,z=3
相关问题
1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12
一道方程组题目 3x-y+2z=13{ 2x+y-3z=11x+y+z =12
{3x+2y+z=13 x+y+2z=7 2x+3y-z=12,求x,y,z
{3x+2y+z=13 {x+y+z=7 {2x+3y-z=12
1,{2x+y+z=-26,x+2y+z=-30,x+y+2z=-28 2,{5x+2y+z=12,4x+3y+z=13
-x+2y+3z=12 2x-2y+5z=13 3x+2y+z=10
2x+y+z=15,x+2y+z=16,x+y+2z=13
2x+y+z=11,x+2y+z=16,x+y+2z=17
解三元一次方程组﹛3y-y+z=3 2x+y-3z=11 x+y+z=12 ﹛x+y-2z=5 2x-y+z=4 2x+
解方程组:-x+2y+3z=12 2x-2y+5z=13 3x+2y+z=10