Question

已知园C的方程x的平方加y的平方减4x加2my加2m的平方减2m加1等于零(1)实数m的取值

Answer 1

x的平方加y的平方减4x加2my加2m的平方减2m加1

=(x-2)^2-4+(y+m)^2+m^2-2m+1

=(x-2)^2+(y+m)^2+m^2-2m-3

=(x-2)^2+(y+m)^2+(m-3)(m+1)=0

(m-3)(m+1)