Question

已知2a-3b+c=0,2a+b-11c=0,且abc≠0,求（a^2-2b^2+3c^2)/(a^2-3b^2-c^2

Answer 1

由2a-3b+c=0,2a+b-11c=0,可知a=4c,b=3c,代入（a^2-2b^2+3c^2)/(a^2-3b^2-c^2)=-1/12