Question

b除以a-b+a除以a+b-2ab除以b的2次方-a的2次方怎样算

Answer 1

/(a-b)+a/(a+b)-2ab/(b^2-a^2)

=[b(a+b)+a(a-b)]/(a-b)(a+b)+2ab/(a^2-b^2)

=(b^2+a^2)/(a-b)(a+b)+2ab/(a-b)(a+b)

=(a^2+b^2+2ab)/(a-b)(a+b)

=(a+b)^2/(a-b)(a+b)

=(a+b)/(a-b)