Question

已知T1,T2都是函数F（x)的周期,怎么求比T1,T2更小的F(x)周期,

Answer 1

T1是函数f(x)的周期,则：f(x)=f(x＋T1)

同理,有：f(x)=f(x＋T2)

则：f(x＋T1)=f(x＋T2) =====>>>> f(x＋T1)=f[(x＋T1)＋(T2－T1)]

则周期是T=|T2－T1|