Question

计算机导论利用率补码计算105-47求过程,

Answer 1

x =105d =110 1001b

[x]补 =0110 1001b

.

-y = -47d = -10 1111b

[-y]原 =1010 1111b

[-y]反 =1101 0000b

[-y]补 =1101 0001b

.

[x]补 =0110 1001b

[-y]补 =1101 0001b (+

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［x-y]补 =0011 1010b 最高位符号位进1自然丢失

x-y =0011 1010b =3Ah =58d