Question

x^2-3x+1=0 2x^2+6=7x 3x^2-9x+2=0

Answer 1

x^2-3x+1=0

(x-3/2)^2-9/4+1=0

(x-3/2)^2=5/4

x-3/2=±1/2√5

x=(3±√5)/2

2x^2+6=7x

2x^2-7x+6=0

(2x-3)(x-2)=0

x1=3/2 x2=2

3x^2-9x+2=0

x^2-3x+2/3=0

(x-3/2)^2=9/4-2/3=27/12-8/12=19/12

x-3/2=±1/6√57

x=3/2±1/6√57