Question

函数y等于sin括号X减3分之兀当X为何值取最值和求函数单调区间

Answer 1

0≤x≤π/2

π/3≤x+π/3≤5π/6

所以当x+π/3=π/3,即x=0时取得最小值y=sinπ/3=√3/2

当x+π/3=π/2,即x=π/6时取得最大值y=sinπ/2=1

令π/3≤x+π/3≤π/2

得 0≤x≤π/6

故单调增区间：[0,π/6]

令π/2＜x+π/3≤5π/6

得π/6＜x≤π/2

故单调减区间：(π/6,π/2]

自己模仿一下吧