Question

1.mx+y+z=m+1x+my+z=m+2x+y+mz=m+32.(m+1)x-(2m-1)y=3m(3m+1)x-(

Answer 1

1、(3)-(2):(1-m)y+(m-1)z=1.(4)

m*(2)-(1):(m^2-1)y+(m-1)z=m^2+m-1...(5)

(5)-(4):(m^2+m-2)y=m^2+m-2 y=1 (题目隐含了m恒不为1)

由此,易得：z=m/(m-1),x=(m-2)/(m-1)

2、(3m+1)*(1)-(m+1)*(2):y=-(2m+1)/m

x=(1-m)/m 此题隐含了m不等于2,0