Question

求函数log2（x+1/x-1）的反函数.

Answer 1

y=log(2)[(x+1)/(x-1)]

2^y=(x+1)/(x-1)

(2^y)(x-1)=x+1

x*2^y-2^y=x+1

(2^y-1)x=2^y+1

x=(2^y+1)/(2^y-1)

反函数y=(2^x+1)/(2^x-1)

x不等于0

2^x表示2的x次方