求关于函数极限的题22题是 X的3次方. - 知识问答

求关于函数极限的题22题是 X的3次方.

1个回答

原式=lim(x->1)(3x²-3)/(3x²-5)
=(3-3)/(3-5)
=0
(4)原式=lim(x->+∞)(2lnx·1/x)/1
=lim(x->+∞)2lnx/x
=lim(x->+∞)(2/x)/1
=0
(6)原式=lim(x->0)(1-1/(x+1))/2x
=lim(x->0)(x/(x+1))/2x
=lim(x->0)(1/(x+1))/2
=1/2

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