延长CD,过B点作CD延长的垂线交于E点
AD=DB,∠CDA=∠BDE,
=>Rt△CDA≌Rt△BDE
=>AC=BE,DC=DE
tan∠DCB=BE/CE=1/3
tan∠A=DC/AC=1/2CE/BE=3/2
AC=6
DC=9
AD=√117=3√13
AB=2AD=6√13
延长CD,过B点作CD延长的垂线交于E点
AD=DB,∠CDA=∠BDE,
=>Rt△CDA≌Rt△BDE
=>AC=BE,DC=DE
tan∠DCB=BE/CE=1/3
tan∠A=DC/AC=1/2CE/BE=3/2
AC=6
DC=9
AD=√117=3√13
AB=2AD=6√13