Question

计算(3a的n+1次方-6a的n次方+9a的n-1次方)除以(3分之1a的n-2次方)

Answer 1

﹛3a^(n+1)-6a^n+9a^(n-1)﹜/1/3*a^(n-2)

=﹛3a^(n-2)*a^3-3a^(n-2)*2a^2+3a^(n-2)*3a﹜/1/3*a^(n-2)

=9a^3-6a^2+9a