Question

(a-b+c)的3次方*（b-a-c)的5次方*（a-b+c)的6次方 (b-a)的m次方*（b-a)n-5次方*（a-

Answer 1

1.原式=(a-b+c)^3 * [-(a-b+c)]^5 * (a-b+c)^6

=(a-b+c)^(3+6) * (-1)^5 * (a-b+c)^5

=(a-b+c)^9 * (-1) *(a-b+c)^5

=-(a-b+c)^(9+5)

=-(a-b+c)^14

2.原式=(b-a)^m * (b-a)^(n-5) * [-(b-a)]^5

=(b-a)^(m+n-5) * (-1)^5 * (b-a)^5

=-(b-a)^(m+n-5+5)

=-(b-a)^(m+n)