∵a=1
f = (x^2 - x + 1) e^x
f(1) = e
即:切点为:(1,e)
切点的斜率为:f' = ( 2x - 1) e^x + (x^2 - x + 1) e^x
f'(1) = e
切线方程为:y - e = f'(1)(x-1)
y=ex
∵a=1
f = (x^2 - x + 1) e^x
f(1) = e
即:切点为:(1,e)
切点的斜率为:f' = ( 2x - 1) e^x + (x^2 - x + 1) e^x
f'(1) = e
切线方程为:y - e = f'(1)(x-1)
y=ex