Question

解二元一次方程 (X^2-3X+3)(X^2-3X+1)=8

Answer 1

(X^2-3X+3)(X^2-3X+1)=(X^2-3X+2+1)(X^2-3X+2-1),X^2-3X+2看着a,得(a+1)(a-1)=a^2-1,即(X^2-3X+3)(X^2-3X+1)=(X^2-3X+2)^2-1=8,移项,得

X^2-3X+2=3或X^2-3X+2=-3,呵,后面我就不写了.